反转字符串
题目
leetcode｜反转字符串
难度: 简单
题解/思路
双指针
- 空间复杂度O(1)
- 时间复杂度O(n)
```
/**
- @param {character[]} s
- @return {void} Do not return anything, modify s in-place instead.
*/
var reverseString = function(s) {
let left = 0;
let right = s.length - 1;
while (left < right) {
[s[left], s[right]] = [s[right], s[left]];
left++;
right–;
}
return s;
};
````